To Display an Image in Devexpress XtraGrid Control using C# and VB.NET see the example below.

Sample C#

#region

using System.Data;
using System.Drawing;
using System.Windows.Forms;
using WindowsFormsApplication77.Properties;
using DevExpress.XtraEditors.Repository;

#endregion

namespace de.fesslersoft.XtraGridImageTest
{
    public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
            gridControl1.DataSource = CreateTable(3);
            gridView1.Columns["Image"].ColumnEdit = new RepositoryItemPictureEdit();
        }

        private DataTable CreateTable(int rowCount)
        {
            var image = Resources.Image1;
            var tbl = new DataTable();
            tbl.Columns.Add("ID", typeof (int));
            tbl.Columns.Add("URL", typeof (string));
            tbl.Columns.Add("Image", typeof (Image));
            for (var i = 0; i < rowCount; i++)
            {
                tbl.Rows.Add(new object[] {i, "http://codesnippets.fesslersoft.de", image});
            }
            return tbl;
        }
    }
}

Sample VB.NET

#Region ""

Imports System.Data
Imports System.Drawing
Imports System.Windows.Forms
Imports WindowsFormsApplication77.Properties
Imports DevExpress.XtraEditors.Repository

#End Region

Namespace de.fesslersoft.XtraGridImageTest
	Public Partial Class Form1
		Inherits Form
		Public Sub New()
			InitializeComponent()
			gridControl1.DataSource = CreateTable(3)
			gridView1.Columns("Image").ColumnEdit = New RepositoryItemPictureEdit()
		End Sub

		Private Function CreateTable(rowCount As Integer) As DataTable
			Dim image = Resources.Image1
			Dim tbl = New DataTable()
			tbl.Columns.Add("ID", GetType(Integer))
			tbl.Columns.Add("URL", GetType(String))
			tbl.Columns.Add("Image", GetType(Image))
			For i As var = 0 To rowCount - 1
				tbl.Rows.Add(New Object() {i, "http://codesnippets.fesslersoft.de", image})
			Next
			Return tbl
		End Function
	End Class
End Namespace

Result

XtraGrid ColumnImages